102 is divisible by: 1 2 3 6 17 34 51 102.
102 For a number to be divisible by 6, it must be divisible by both 2 and 3. 102 div by 2 = 51; 102 div by 3 = 17
102 as 102/2 = 51 102/3 = 34
Yes but it will have a remainder of 2
No, 102 ÷ 4 = 25 r 2. To check for divisibility by 4, if the last 2 digits are divisible by 4, the whole number is, otherwise the remainder is the same: 102: last 2 digits are '02' = 2 2 ÷ 4 = 0 r 2, so 102 ÷ 4 has remainder 2.
102 is divisible by: 1 2 3 6 17 34 51 102.
102 For a number to be divisible by 6, it must be divisible by both 2 and 3. 102 div by 2 = 51; 102 div by 3 = 17
The factors of 102 are 1, 2, 3, 6, 17, 34, 51, and 102. So it is composite with eight factors.
102 as 102/2 = 51 102/3 = 34
Yes, 204 / 2 = 102
A prime number is divisible only by itself - 102 is divisible by 2 and 51 so it is not a prime.
102
Yes but it will have a remainder of 2
No, 102 ÷ 4 = 25 r 2. To check for divisibility by 4, if the last 2 digits are divisible by 4, the whole number is, otherwise the remainder is the same: 102: last 2 digits are '02' = 2 2 ÷ 4 = 0 r 2, so 102 ÷ 4 has remainder 2.
Yes 102 is indeed divisible by 6. A simple way to find out if a number is divisible by six is the divisibility rules. For 6, Check if the number ends in a even number such as 0, 2, 4, 6, or 8. Then, add the digits of your number and check if it is any number which is a multiple of 3. For example, 102 ends in 2 1+0+2=3 102 is divisible by 6.
100 is divisible by 1, 2, and 5. 1 is not itself a prime number; 101 is a prime; 102/2 =51 102/3 =34 102/17=6
A prime number is divisible only by itself - 102 is divisible by 2 and 51 so it is not a prime.A prime number is divisible only by 1 and itself.102 is a composite number because it is divisible by 2, 17, and 51 as well as by 1 and itself.Every even number (except 2) is composite.