Yes but it will have a remainder of 2
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Yes. Every non-zero number is divisible by itself.
102 is divisible by: 1 2 3 6 17 34 51 102.
102 For a number to be divisible by 6, it must be divisible by both 2 and 3. 102 div by 2 = 51; 102 div by 3 = 17
Yes, 102 divided by 2 = 51.
Because is shows 1020 is divisible by 10 and everything that divides by 10, also divides by 5 and 2, because 10 itself divides by 5 and 2.