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The sum of its digits is 1+2+0 = 3 which is divisible by 3. So 120 is divisible by 3. The number 120 ends in a 0 and so it is divisible by 5.
Yes, it is divisible by both. 120 is even, so it is a multiple of 2; 1 + 2 + 0 = 3 which is one of 3, 6, 9, so it is a multiple of 3.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
30, 60, 90, 120, 150, 180...
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.