The sum of its digits is 1+2+0 = 3 which is divisible by 3. So 120 is divisible by 3. The number 120 ends in a 0 and so it is divisible by 5.
Yes, it is divisible by both. 120 is even, so it is a multiple of 2; 1 + 2 + 0 = 3 which is one of 3, 6, 9, so it is a multiple of 3.
30, 60, 90, 120, 150, 180...
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
The sum of its digits is 1+2+0 = 3 which is divisible by 3. So 120 is divisible by 3. The number 120 ends in a 0 and so it is divisible by 5.
120 is divisible by the following numbers: 1 2 3 4 5 6 8 10 12 15 20 24 30 40 60 120.
Yes, it is divisible by both. 120 is even, so it is a multiple of 2; 1 + 2 + 0 = 3 which is one of 3, 6, 9, so it is a multiple of 3.
30, 60, 90, 120, 150, 180...
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Quite a few. 120, 150, 180 and so on.
No, 120 is not the smallest number that is divisible by 1,2,3,4,5 and 6.
120 is divisible by 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60 and 120.
It is evenly divisible by 2 and 10 but not by 3 and 9.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
Yes, 120 is divisible by 3. A good rule of thumb for the multiples of 3 is to add up the digits in the number. If the number that comes out is divisible by 3, then it is a multiple of 3. For example, in 120, 1 + 2 + 0 = 3. Therefore, the number is divisible by 3. The process can be repeated for larger numbers. For example, 2688 is divisible by 3 because 2 + 6 + 8 + 8 = 24, and 2 + 4 = 6.