even
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To do that, we'll need the factor pairs of 120. (120, 1) (60, 2) (40, 3) (30, 4) (24, 5) (20, 6) (15, 8) (12, 10) Choose the pairs that have an odd and even number. Looks like 4 of them.
None that are all odd numbers. But, there are two sets of three consecutive numbers containing a mix of even/odd that add up to 120. They are 39, 40 and 41 and also 38, 40 and 42.
Yes it would Even + even = even Even + odd = odd Odd + odd = even
There are no numbers between 108 and 120 that have an even ten's digit. If you call 'zero' an even number, then ' 109 ' would qualify. But the whole exercise is still not too satisfying.
because that's the theory of maths even x even = even even x odd = odd even + even = even even + odd = odd