To determine if 1242 is divisible by 23, you would perform the division 1242 ÷ 23. The quotient is approximately 54.08696. Since the quotient is not a whole number, 1242 is not evenly divisible by 23.
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2 and any multiple thereof up to 1242.
The PF of 1242 is: 2 x 3 x 3 x 3 x 23
23 is a prime number so it is not divisible by 3. It is only divisible by 1 and 23. Dividing 23 by three gives the result of 7.6r
23 is not divisible by 7.
161 is evenly divisible by: 1, 7, 23, 161.
2 and any multiple thereof up to 1242.
The LCM of 23 and 54 is 1242.
The PF of 1242 is: 2 x 3 x 3 x 3 x 23
1, 2, 3, 6, 9, 18, 23, 27, 46, 54, 69, 138, 207, 414, 621, 1242
Factorization: 2*3*3*3*23
(including each only once) 2, 3, 23
Only 1 and 23.
23 is a prime number so it is not divisible by 3. It is only divisible by 1 and 23. Dividing 23 by three gives the result of 7.6r
All 16 of these: 1 2 3 6 9 18 23 27 46 54 69 138 207 414 621 1242.
No. 23 is not divisible by anything except itself and one.
23 is not divisible by 7.
To find the least number that divides 285 and 1249 leaving remainders of 9 and 7 respectively, we need to find the difference between the numbers and the remainders. The difference between 285 and 9 is 276, and the difference between 1249 and 7 is 1242. The least number that divides both 276 and 1242 is their greatest common divisor (GCD), which is 6. Therefore, the least number that divides 285 and 1249 leaving remainders 9 and 7 is 6.