Yes. 1,305/3=435. In the future, you can check the divisibility of numbers as follows:
2=digit in one's place is even
3=sum of digits is a multiple of 3
4=last 2 digits are divisible by 4
5=digit in one's place is either 5 or 0
6=satisfies divisibility rule for both 2 and 3
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1, 3, 5, 9, 15, 29, 45, 87, 145, 261, 435, 1305.
The multiples of 145 (which are infinite) are all divisible by 145 , including these: 290, 435, 580, 725, 870, 1015, 1160, 1305, 1450 . . .
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
Not evenly. A number is divisible by 3 if the sum of its digits is divisible by 3.