No. 12.5 is nearer. But 12.5 is not the nearest because 12.05 is nearer. But again, 12.05 is not the nearest because 12.005 is nearer. Rational (and real) numbers are infinitely dense. That means that there are infinitely many numbers between any two numbers and so NO number is nearest to any other: it is always possible to find infinitely many numbers that are nearer.
If rounding to the nearest whole number, it is closer to 13 than to 12.
Your question is somewhat unclear. If the 12 represents dollars, it is 80 cents; if the 12 represents cents, it is 13.
To the nearest whole number it founds off to 12
-13 is an integer.
13
To the nearest whole number, 13
12.80 rounds to 12.8
125 is approximate to:0 to the nearest thousand100 to the nearest hundred130 to the nearest ten
12 x two thirds is 8. 12 and two thirds estimated to the nearest whole number is 13.
Rounded to the nearest dollar, $12.78 (that is, 12 dollars and 78 cents) is approximately equal to $13.
If rounding to the nearest whole number, it is closer to 13 than to 12.
The square root of 150 will be between 12 and 13, closer to 12.
12.5 to the nearest whole number is 12. When rounding a decimal number to the nearest whole number, you look at the digit immediately to the right of the decimal point. If it is 5 or greater, you round up; if it is less than 5, you round down. In this case, 12.5 is closer to 13 than to 12, so it rounds up to 13.
Your question is somewhat unclear. If the 12 represents dollars, it is 80 cents; if the 12 represents cents, it is 13.
That depend upon what you are rounding to: To the nearest thousandth, 6.048 → 6.048 To the nearest hundredth, 6.048 → 6.05 To the nearest tenth, 6.048 → 6.0 To the nearest whole number, 6.048 → 6 To the nearest 2, 6.048 → 6 To the nearest 3, 6.048 → 6 To the nearest 4, 60.48 → 8 To the nearest 5, 6.048 → 5 To the nearest 6, 6.048 → 6 To the nearest 10, 6.048 → 10 To the nearest 12, 6.048 → 12 To the nearest 13 (or higher) 6.048 → 0
12
Rounding 13 to the nearest ten would be 10