The number 141 is a product of two numbers that are factors of 141. To find these numbers, we need to factorize 141 into its prime factors, which are 3 and 47. Therefore, 3 times 47 equals 141.
Make the divisor (1.41) a whole number and then divide normally. To make the divisor a whole number, the easiest way is to keep multiplying it by 10 until it becomes a whole number; but remember, division is just like a fraction - whatever you do to the denominator (bottom) you must also do to the numerator (top) - so whatever you do to the divisor (the number by which you are dividing) you must do to the dividend (the number into which you are dividing): 0.5 ÷ 1.41 = 50 ÷ 141 (multiply both by 100) = 50/141 ≈ 0.3546
139 and 141.
141
141+20=161, 161/7=23. The answer is 23. It is algebra
141 is a composite because 1, 3, and 47 goes in it
47*3 = 141 therefore not a prime number
The number 141 is a product of two numbers that are factors of 141. To find these numbers, we need to factorize 141 into its prime factors, which are 3 and 47. Therefore, 3 times 47 equals 141.
Make the divisor (1.41) a whole number and then divide normally. To make the divisor a whole number, the easiest way is to keep multiplying it by 10 until it becomes a whole number; but remember, division is just like a fraction - whatever you do to the denominator (bottom) you must also do to the numerator (top) - so whatever you do to the divisor (the number by which you are dividing) you must do to the dividend (the number into which you are dividing): 0.5 ÷ 1.41 = 50 ÷ 141 (multiply both by 100) = 50/141 ≈ 0.3546
If this is 9 and 6/15, then in fraction mode, it would be 141/15. 1) Multiply the whole number times the denominator (9 x 15 = 135). 2) Add 135 to the numerator (135 + 6 = 141) 3) Place 141 over the denominator (141/15).
Lanthanum's atomic number is 57 thus it has 57 protons, the number of protons an atom has is equal to the atomic weight, in this case 141 minus the number of protons or 57 so, 141-57=84 Lanthanum-141 has 84 neutrons.
I am not sure what you are asking but 141 is divisible by the number 1, itself (141) and certainly by the number 3 so it is not a prime number.
its 141
139 and 141.
Any real number is divisible by any other real number
141 is a composite number. A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1 and 0. 1 and 0 have a different name.
141