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No.

All multiples of 8 are even, but 141 is odd, so 141 is not divisible by 8.

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To test if a number is divisible by 8, add 4 times the hundreds digit to 2 times the tens digit to the ones digit; if this sum is divisible by 8, then so is the original number. The test can be repeated on the sum, so continue the summing process until a single digit remains - only if this single digit is an 8 is the original number divisible by 8.

141 → 4 × 1 + 2 × 4 + 1 × 1 = 13

13→ 4 × 0 + 2 × 1 + 3 = 5

5 is not 8, so 141 is not divisible by 8

141 ÷ 8 has a remainder of 5.

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