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Q: Can 141 be divisible by 4?

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No. 141 is not evenly divisible by four.

141 can be divisible by 3. As you can see 141/3 = 47.

Yes because 564/4 = 141

it is divisible by 3 which is 141

No. All multiples of 8 are even, but 141 is odd, so 141 is not divisible by 8. ------------------------------------------ To test if a number is divisible by 8, add 4 times the hundreds digit to 2 times the tens digit to the ones digit; if this sum is divisible by 8, then so is the original number. The test can be repeated on the sum, so continue the summing process until a single digit remains - only if this single digit is an 8 is the original number divisible by 8. 141 → 4 × 1 + 2 × 4 + 1 × 1 = 13 13→ 4 × 0 + 2 × 1 + 3 = 5 5 is not 8, so 141 is not divisible by 8 141 ÷ 8 has a remainder of 5.

No.

No. 141 is not evenly divisible by nine.

Yes, because 141 is a multiple of 3.

Yes.

Any element of the set of numbers of the form 141*k where k is an integer.

I'm not quite sure about that theory, but if all the numbers in the number add up to a number that's dividable by 3, then the number itself would then be divisible by 3. Ex. 141 1+4+1= 6 6 is divisible by 3, so 141 is too. 141/3= 47.

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