Yes, it is.
The digital root of 1430061, that is, the sum of all its digits is 1+4+3+0+0+6+1 = 15
The digital root of 15 is 1+5 = 6 which is divisible by 3.
So 1430061 is divisible by 3.
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Three is a factor of nine.
2 and 3Today, people don't explain why a number has to be divisible by 2 and 3 to be divisible by 6 or how it works.
At least one of the four will be divisible by 4. One other will be divisible by 2 (but not by 4) One other will be divisible by 3. Hence the product will be divisible by 4 x 2 x 3 = 24.
21 has factors other than 1 and itself, so it is not a prime number. For example, it is divisible by 3. (You can check this by adding the digits of the number: 2 + 1 = 3. If the sum of the digits is divisible by 3, the number is also divisible by 3.) Therefore, 21 is a composite number.
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.