Composite - it's exactly divisible by three. 1x153 and 3x51.
It goes down to 1/17 or 1 over 17. This is because both the top and bottom are divisible by 9.
1, 3, 7, 9, 17, 21, 51, 63, 119, 153, 357, 1071.
There are six such numbers: 153, 162, 171, 180, 189, 198.
1, 3, 9, 17, 51, 131, 153, 393, 1179, 2227, 6681, 20043
No, 153 is only divisible by: 1, 3, 9, 17, 51, 153.
Composite - it's exactly divisible by three. 1x153 and 3x51.
1,377 is divisible by: 1, 3, 9, 17, 27, 51, 81, 153, 459, 1377.
All the numbers are divisible by: 9
No, 49 cannot be divided by 3 evenly. 43 divided by 3 is equal to 16⅓. A general way of knowing if a number is divisible by 3 is by finding the sum of the individual numbers that is being divided. If the sum itself is divisible by 3, then the number is likewise also divisible. For example, the problem stated is 49/3. In 49, 4+9=13. Because 13 is not evenly divisible by 3, 49 also cannot be evenly divided by 3. In another example, the problem stated is 153/3. In 153, 1+5+3=9. Because 9 is divisible by 3, 153 is also likewise divisible by 3. 153/3=51.
1,3,9,17,51,153
Nope. 9,333 is divisible by 1, 3, 9, 17, 51, 61, 153, 183, 549, 1037, 3111, 9333.
1, 3, 9, 17, 51, 153, 289, 867, 2601.
According to my calculations, the following are evenly divisible by 9: 108, 117, 126, 135, 144, 153, 162, 171, 180, 189, and 198.
It goes down to 1/17 or 1 over 17. This is because both the top and bottom are divisible by 9.
1, 3, 9, 17, 51, 153, 5189, 15567, 46701, 88213, 264639, 793917.
1, 3, 7, 9, 17, 21, 51, 63, 119, 153, 357, 1071.