No, 49 cannot be divided by 3 evenly. 43 divided by 3 is equal to 16⅓. A general way of knowing if a number is divisible by 3 is by finding the sum of the individual numbers that is being divided. If the sum itself is divisible by 3, then the number is likewise also divisible.
For example, the problem stated is 49/3. In 49, 4+9=13. Because 13 is not evenly divisible by 3, 49 also cannot be evenly divided by 3.
In another example, the problem stated is 153/3. In 153, 1+5+3=9. Because 9 is divisible by 3, 153 is also likewise divisible by 3. 153/3=51.
Besides 49 & 98? The numbers divisible by 49 are infinite.
Yes. The answer is 49.
The divisibility rule for 3 is as follows: If the sum of the digits of a number is divisible by 3 then the number is divisible by 3. For example, the number 21 is divisible by 3 since 2+1=3, and 3 is divisible by 3. The number 49 is not divisible by 3 since 4+9=13, and 13 is not divisible by 3.
1, 3, 7, 9, 21, 49, 63, 147, 441
Yes: 49 ÷ 7 = 7
No, 3 cannot go into 49 evenly because 49 is not divisible by 3 without leaving a remainder.
1, 3, 49, and 147
1, 3, 49, and 147
No. 49 is only divisible by 1, 7 and 49.
Besides 49 & 98? The numbers divisible by 49 are infinite.
Yes. The answer is 49.
No, but 98 is evenly divisible by 1, 2, 7, 14, 49, 98.
The divisibility rule for 3 is as follows: If the sum of the digits of a number is divisible by 3 then the number is divisible by 3. For example, the number 21 is divisible by 3 since 2+1=3, and 3 is divisible by 3. The number 49 is not divisible by 3 since 4+9=13, and 13 is not divisible by 3.
All multiples of 49 are divisible by it. Ex: 49, 98, 147 etc
The factors of 18 are: 1, 2, 3, 6, 9, 18 The factors of 49 are: 1, 7, 49
49 is divisible by 1, 7 and 49
The reason is that 49 is divisible with numbers other than 1 and itself. 49 is divisible by 1, 7 and 49.