It goes down to 1/17 or 1 over 17. This is because both the top and bottom are divisible by 9.
No, and here is why: If you want to find out of a number is divisible by 3, you add up the numerals in the number, and see if that total is divisible by 3. In this case, we find that 2+6+9+0 equals 17. 17 is not divisible by 3, therefore, 2690 is not divisible by 3 either.
NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)
Every multiple of 17 is divisible by 17. There are an infinite number of them.
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
4,165 / 17 = 245
No it's not. For a number to be divisible by 9, the sumof the digits must also be divisible by 9. These digits add up to 17
156/9 = 17 with a remainder of 3 or 17 and 3/9 or 17 and 1/3 or 17.333333
150 ÷ 9 = 16 r 6 → the first natural number between 150 and 300 divisible by 9 is 9 × 17 (=154)300 ÷ 9 = 33 r 3 → the last natural number between 150 and 300 divisible by 9 is 9 × 33 (=297)→ there are 33 - 17 + 1 = 17 natural numbers between 150 and 300 divisible by 9.
No, 153 is only divisible by: 1, 3, 9, 17, 51, 153.
No. To check for divisibility by 9 add the digits together and if this sum is divisible by 9 then so is the original number. This can be repeated until a single digit remains which must be 9 for the original number to be divisible by 9. For 98: 9 + 8 = 17 → 1 + 7 = 8 which is not 9, so 98 is not divisible by 9.
not evenly. it divides into 161 - 17 and 8/9 times i think
1,377 is divisible by: 1, 3, 9, 17, 27, 51, 81, 153, 459, 1377.
It goes down to 1/17 or 1 over 17. This is because both the top and bottom are divisible by 9.
No, and here is why: If you want to find out of a number is divisible by 3, you add up the numerals in the number, and see if that total is divisible by 3. In this case, we find that 2+6+9+0 equals 17. 17 is not divisible by 3, therefore, 2690 is not divisible by 3 either.
The digits add up to 17, which is not a multiple of 3. So no.
All multiples of 17 are divisible by 17. There is an infinite number of multiples of 17.