Since 1845 is an odd number, it can't be divisible by 2, 6 or 10. It is divisible by 3, 5 and 9.
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It is evenly divisible by 3, 5 and 9 but not by 2, 6 or 10.
The factors of 1845 are: 1, 3, 5, 9, 15, 41, 45, 123, 205, 369, 615, and 1845.The prime factors of 1845 are: 3, 5, and 41.
Here are possibilities of what you mean: a: (3-2)(x-2)=10 Solution: (3-2)(x-2)=10 1(x-2)=10 x-2=10/1 x=10+2=12 b: 3-2(x-2)=10 Solution: 3-2(x-2)=10 3-10=2(x-2) -7=2x-4 -3=2x x=-3/2=-1.5
10 - 3 + 2 = 2 is a false statement. 10 - 3 + 2 = 9
2/3 ÷ 3/10 = 2/3 × 10/3 = 20/9 = 2 2/9