It is evenly divisible by 3, 5 and 9 but not by 2, 6 or 10.
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Since 1845 is an odd number, it can't be divisible by 2, 6 or 10. It is divisible by 3, 5 and 9.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.
It is evenly divisible by 2 and by 3.