The answer to that will depend on what operator is supposed to be in place between the "1" and the "4y".
If it's 1 + 4y = 12 - 4x, then yes, that is linear. It would give you the line described by the equation y = 8/3 - x, which is a simple line with a slope of negative one, which intersects the axis at points (0, 8/3), and (8/3, 0).
If it's multiplication, 1 * 4y = 12 - 4x (or if that "1" is just a question number that you cut and pasted out of your homework), then this is also linear, also has a slope of -1, but intersects both axis at the point (0, 0).
If on the other hand, you mean 14y = 12 - 4x, then yes, that is also linear. This is because 1 to the power of anything is equal to one. That tells us that:
12 - 4x = 1
∴ -4x = -11
∴ x = 11/4
Which means that the equation describes a vertical line that passes through x-axis at (11/4, 0).
If you mean 1/4y = 12 - 4x, then no, this is not linear:
1/(4y) = 12 - 4x
∴4y = 1/(12 - 4x)
∴y = 1/(48 - 16x)
That would instead give you a curve where y approaches infinity as x approaches 0 and y approaches 0 as x approaches infinity.
Yes.
10
Yes.
3x - 4y = 14 is a linear equation in two variables. It is also the equation of line.
Let's simplify it ... (4y-2x) = 0 = (2y -x ) = 0 2y = x y = x/2 Yes, it is linear.
Yes.
10
Yes.
No, it is not.
3x - 4y = 14 is a linear equation in two variables. It is also the equation of line.
Let's simplify it ... (4y-2x) = 0 = (2y -x ) = 0 2y = x y = x/2 Yes, it is linear.
Looks like a linear equation to me, and a ridiculously easy one at that.
dy/dx = 5/4
No. It's a quadratic equation, and it has two solutions.
It is not possible to solve a single linear equation in two unknown variables.
To function form. - 7X - 4Y = 16 - 4Y = 7X + 16 Y = - 7/4X - 4 ------------------------ The slope is, - 7/4 --------
Yes it is a function. 5x + 4y = 0 the same as: 5x = -4y You can also solve for either variable. x = - ( 4 / 5 ) y y = - ( 5 / 4 ) x