4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80
42+4y -12 = 13y -12 -2y 4y -13y+2y = 12 -12 -42 -7y = -42 y = 6
3x - 2y + 7x + 4y = 3x + 7x - 2y +4y = (3+7)x + (-2+4)y = 10x + 2y
Y squared (Y^2)
Answers to pick: -2x - y = 4 2x + y = -2 -8x + 4y = -16 -4x + 2y = -8 -x - 2y = 6 -7x + 4y = 16 2x + 3y = 6 3x + 2y = 4
(5x - 2y)(5x + 2y)
The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
The points of intersection of the equations 4y^2 -3x^2 = 1 and x -2 = 1 are at (0, -1/2) and (-1, -1)
4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80
9y cubed plus 2y squared
2y + 1
3x - 2y = 20 Substitute x = 4y into this equation: 3(4y) - 2y = 20 ie 12y - 2y = 20 10y = 20 so that y = 2 and then x = 4y gives x = 2*4 = 8
4y + 4 = 2y + 12Subtract 2y from each side of the equation:2y + 4 = 12Subtract 4 from each side:2y = 8Divide each side by 2:y = 4
4y + 4 = 2y + 12Subtract 4 from each side of the equation:4y = 2y + 8Subtract 2y from each side:2y = 8Divide each side by 2 :y = 4
(8, 2)