No, it is not.
Numbers up to 200 divisible by both 2 and 3 = numbers to 200 divisible by 2*3 = 6 which is int(200/6) = int(33.33) = 33
50 of them.
There are 33 such numbers.
50 of them.
A multiple of 5 between 100 and 200 that is also divisible by both 4 and 6 is 120. It meets these criteria because 120 is a multiple of 5 (24 x 5 = 120), divisible by 4 (120 ÷ 4 = 30), and divisible by 6 (120 ÷ 6 = 20). Other multiples of 5 in that range, like 125 or 130, do not meet the divisibility requirements for 4 and 6.
Numbers up to 200 divisible by both 2 and 3 = numbers to 200 divisible by 2*3 = 6 which is int(200/6) = int(33.33) = 33
Yes, 1,200 divided by 6 is 200.
A number that is divisible by 4 and 6 must be divisible by the LCM of 4 and 6 which is 12. 100/12 = 8.33 200/12 = 16.67 So, there are 16 numbers below 200 that are divisible by 4 and 6 and, of these, 8 are smaller than 100. That gives 16 - 8 = 8 between 100 and 200.
6 of them.
100 ÷ 6 = 16 r 4 so the first whole number between 100 and 200 divisible by 6 is 6 x 17 (= 102) 200 ÷ 6 = 33 r 2 so the last whole number between 100 and 200 divisible by 6 is 6 x 33 (= 198) So the whole numbers between 100 and 200 divisible by 6 are the multiples of 6 from 17 to 33 which are: 102, 108, 114, 120, 126, 132, 138, 144, 150, 156, 162, 168, 174, 180, 186, 192 and 198.
50 of them.
6
There are 33 such numbers.
50 of them.
twenty eight
22,200 is a number that can be divisible by 111 and 200.
A multiple of 5 between 100 and 200 that is also divisible by both 4 and 6 is 120. It meets these criteria because 120 is a multiple of 5 (24 x 5 = 120), divisible by 4 (120 ÷ 4 = 30), and divisible by 6 (120 ÷ 6 = 20). Other multiples of 5 in that range, like 125 or 130, do not meet the divisibility requirements for 4 and 6.