100 ÷ 6 = 16 r 4 so the first whole number between 100 and 200 divisible by 6 is 6 x 17 (= 102)
200 ÷ 6 = 33 r 2 so the last whole number between 100 and 200 divisible by 6 is 6 x 33 (= 198)
So the whole numbers between 100 and 200 divisible by 6 are the multiples of 6 from 17 to 33 which are: 102, 108, 114, 120, 126, 132, 138, 144, 150, 156, 162, 168, 174, 180, 186, 192 and 198.
There are 22 such numbers.
150
14:105,112,119,126,133,140,147,154,161,168,175,182,189,196.
6
There are 33 numbers between 200 and 300 that are divisible by three.
There are 22 such numbers.
you can say that 2/10 of every 10 integers is divisible by 5, so multiplying 2/10 by 100, giving you 200/1000 total integers are divisible by 5. half of all integers are odd, so divide 200/1000 by 2 is 100/1000, so you can correctly state that 100 odd integers under 1000 are divisible by 5.
For example, for all numbers between 101-200: for (int i = 101; i
There are 9 integers.
There are (500-100)/2 = 200 numbers divisible by 2 between 100 and 500 counting 100 but not 500. Of these (500-100)/8 = 50 are divisible by 8. So there are 150 numbers between 100 and 500 divisible by two but not by 8. By relative primeness exactly 50 out of these 150 are divisible by 3 and therefore these 50 are exactly the ones divisible by 6 but not by 8.
12. 13, if you count 200
A number that is divisible by 4 and 6 must be divisible by the LCM of 4 and 6 which is 12. 100/12 = 8.33 200/12 = 16.67 So, there are 16 numbers below 200 that are divisible by 4 and 6 and, of these, 8 are smaller than 100. That gives 16 - 8 = 8 between 100 and 200.
150
14 of them
What for? There is only a 154 inside that is divisible by 77...
150
17 of them.