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What is the answer to 16t2-37t plus 20 equals 0?
16t2 - 37t + 20 = 0 Using the quadratic formula, t = [37 +/- sqrt(372 - 4*16*20)]/(2*16) = [37 +/- sqrt(89)] / 32 ie t = 0.861438 or t = 1.451062
How do you find the average value of Q of t over the interval 10 less than or equal to x which is less than or equal to 20 and Q of t equals 4 times .96 t grams?
The bounds of integration are 10 and 20. The function that we are integrating is Q(t)=4(.96t)=3.84t. So the average value of Q(t) from 10 to 20 is equal to [1/(20-10)]*the integral from 10 to 20 of 3.84t dt. Simplifying, we get .384*the integral from 10 to 20 of t dt. Integrating, we get that the average value = .384(20^2 - 10^2)/2 = .196*(400 - 100) = .196 * 300 = 58.8. The average value in question is exactly 58.8 grams.
The pseudocode If-Then statement that assigns 0 to x if y is equal to 20?
Pseudocode is generally a very loosely defined concept. Various ways you can show your statement: if y = 20 then x = 0 if( y == 20 ) x = 0 if y is 20 then set x to 0
What is the average speed at t equals20 s?
That depends upon what the object has done for the 20 seconds since t = 0 seconds.
How do you find the x and y intercept of -5x plus 10y equals 20?
Basically, the x-intercept is what x equals when y=0, and the y-intercept is what y equals when x=0. To find the x intercept, set y equal to 0. -5x+10(0)=20 -5x+0=20 -5x=20 divide both sides by -5 x=-4 so the x intercept is (-4,0) To find the y intercept, set x equal to 0. -5(0)+10y=20 0+10y=20 10y=20 divide both sides by 10 y=2 so the y intercept is (0,2)
