Yes, to test for divisible by 9: add the digits together [2+3+4+0=9]. If the sum equals nine, or a number divisible by nine, then the original number is divisible by nine.
Example: 4752; 4+7+5+2 = 18, which is divisible by 9. If you're not sure, 1+8=9. You can always keep adding the digits together, and eventually you'll be left with a single digit number. If the sum is equal to 9, then the original number is divisible by 9.
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For any larger number for which you have to test divisibility, split this factor up into smaller numbers. For example, you know that 2340 is divisible by 90 because you can divide it by 10 (2340 / 10 = 234), and then you can divide 234 by 9 (234 / 9 = 26).
For a number to be divisible by 90, it must be divisible by both (relatively prime factors) 9 and 10.It ends in a zero, so it is divisible by 10The digits adds up to a multiple of 9, so it is divisible by 9.The answer is yes. 2340 / 90 = 260 ■I know that because if you divide these numbers you get 26. 26 times 90 is 2,340.
780, 1560, 2340 and 3120
780, 1560, 2340 and so on.
Every one of its multiples are. Forgive me if I don't list them. You see, there are an infinite number of them.
The multiples of 780 (which are infinite) are all divisible by 780, including these: 780, 1560, 2340, 3120, 3900, 4680, 5460 . . .
0.0226
Here are some even numbers that are divisible by 5: 10 20 30 40 50 100 600 720 890 1110 2340 3360 108,070 224,560 Any number that is divisible by 10 (which means it ends in "0") is also divisible by 5.
4 times 60 is 240
35% of 2340 = 820.75
The number 2,340 can be divided by the number 9 260 times.