For a number to be divisible by 90, it must be divisible by both (relatively prime factors) 9 and 10.
It ends in a zero, so it is divisible by 10
The digits adds up to a multiple of 9, so it is divisible by 9.
The answer is yes. 2340 / 90 = 260 ■
I know that because if you divide these numbers you get 26. 26 times 90 is 2,340.
==yes. 90 is divisible by 3 and 9==
Well, isn't that a happy little question? Let's take a closer look. If a number is divisible by 5, it must end in 0 or 5. And if a number is divisible by 9, the sum of its digits must also be divisible by 9. When we add the digits of 90 (which is 9 + 0 = 9), we see that it is divisible by 9 but not by 5.
30
2,3,5,6,9,10. Not by 4.
0.0226
For any larger number for which you have to test divisibility, split this factor up into smaller numbers. For example, you know that 2340 is divisible by 90 because you can divide it by 10 (2340 / 10 = 234), and then you can divide 234 by 9 (234 / 9 = 26).
yes because t bnxfjhj
No, 10 is not divisible by 2340. A number is considered divisible by another if it can be divided by that number without leaving a remainder. Since 10 is much smaller than 2340, it cannot be divided evenly by it.
Because 90 divides into 2340 evenly with no remainder.
26
The LCM is 2340.
The LCM is 2340.
26
780, 1560, 2340 and 3120
780, 1560, 2340 and so on.
The number 2,340 can be divided by the number 9 260 times.
26