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No it is not. To check - add all the digits together (in this case 2+6+9=17. If the sum of the digits can be divided exactly by 3, then the number itself will also divide by 3. In this case, 17 (the sum of the digits) does not divide exactly by 3.

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Q: Is 2690 divisble by 3
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What is the remainder when 2690 is divided by 3?

896.6667


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By 2 but not by 3. 2690 is a multiple of 2 because it ends in 0 but it isn't a multiple of 3 because 2 + 6 + 9 = 17 and 17 isn't a multiple of 3


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