26 is be the square root of 676
It is not a perfect square. 5-square = 25 6-square = 36 So there cannot be a perfect square between 25 and 36.
The integer is 26
Any integer ,n, to the 6th. power would be both a perfect square and a perfect cube: This is because (n2 )3 =n6 which is a perfect square and a perfect cube. Or course you could also write this as (n3 )2 =n6 06 = 0 16 = 1 26 = 64 etc.
64. 64 = 82 = 43 26 = (23)2 = (22)3 = 64.
26 is be the square root of 676
If you mean a perfect square, then no. It is between 26*26 and 27*27.
It is not a perfect square. 5-square = 25 6-square = 36 So there cannot be a perfect square between 25 and 36.
The integer is 26
121 is perfect three digit square palindrome. (11 x 11) So is 484 (22 x 22) and 676 (26 x 26)
The factors of 26 are 1, 2, 13, and 26. None of them are perfect squares. It can't be simpified further.
Any integer ,n, to the 6th. power would be both a perfect square and a perfect cube: This is because (n2 )3 =n6 which is a perfect square and a perfect cube. Or course you could also write this as (n3 )2 =n6 06 = 0 16 = 1 26 = 64 etc.
64. 64 = 82 = 43 26 = (23)2 = (22)3 = 64.
26
200 is not a perfect square. Its square root is a fraction and the square root of a perfect square is always an integer.
No, 325 is not a perfect square however 324 is a perfect square.
8, 10 24, 26