121 is perfect three digit square palindrome. (11 x 11)
So is 484 (22 x 22) and 676 (26 x 26)
729
729, cube of 9 and square of 27
There are a total of 5 positive three-digit perfect cubes that are even. To find this, we first determine the range of three-digit perfect cubes, which is from 46 to 96. Then, we identify the even perfect cubes within this range, which are 64, 216, 512, 729, and 1000.
Well, let's see. Perfect cubes that are two digits: 27 64 Could it be 27? Well, 2+7 is 9, and that's a perfect square with a square root of 3, and the cube root of 27 is three. Looks like we've found our answer, especially since 6+4 = 10, which is NOT a perfect square.
Oh, dude, there are 90 three-digit palindromic numbers. You see, a three-digit palindrome has the form "ABA," where A and B can be any digit from 1 to 9. So, you just multiply the possibilities for A and B, which is 9 choices each, and voilà, you get 9 x 10 = 90. Easy peasy, lemon squeezy!
121
102 = 100 which is the first possible three digit number that is a perfect square. 312 = 961 which is the last possible three digit number that is a perfect square. So there are 22 three digit positive numbers that are perfect squares.
1, 2, 3
729
It is 10.
343 7*7=49 49*7=343
729, cube of 9 and square of 27
961 961
x64 is not a perfect square any number if it is a 3-digit perfect square and ending with 4 it can be 144,324 ,484 and 784 because the number is ending with 4 but the tens digit is not matching to any of the option so it is not a perfect square
It is: 31*31 = 961
999
929