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Set up algebraically. X = what X/2769 = 5 2769/1*(X/2769 = 5)*2769/1 multiply through by 2769 X = 13845 ------------- check 13845/2769 = 5 5 = 5 checks
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
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Not evenly. A number is divisible by 3 if the sum of its digits is divisible by 3.