0
I'm not sure what you mean. Two and seven are not divisible by nine so if you mean that the answer would be no.
Two hundred seventy nine divided by nine is 31 so that answer would be yes.
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
Is 1 2 7 3 6 divisible by 4 and 9?
1, 2, 7, 3 and 6 are not divisible by 4 and/or 9. 12736 is divisible by 4 but not by 9.
767 divisible by 9?
no 7 + 6 + 7 = 20 = 2 + 0 = 2 numbers divisible by 9 add up to 9 85.2222 = 767 / 9
Is 24207 divisible by 9?
Nope - in order for a number to be divisible by 9, the sum of its digits must also be divisible by 9. In this case, the digits 2+4+2+7=15.
What number is not divisible by 600 2 3 5 or 9?
7 is not divisible by any of them.
Are 14 and 63 divisible by the same number?
Yes they are. They are both divisible by 7. 14/2= 7 and 63/9=7
767 divisible by 9?
no 7 + 6 + 7 = 20 = 2 + 0 = 2 numbers divisible by 9 add up to 9 85.2222 = 767 / 9
Is 267 divisible by 9?
No, because for a number to be divisisble by 9, it's digits (2,6 & 7) must add together to produce a number divisible by 9. 2+6+7=8+7=15. Is 15 divisible by 9? No, so we can conclude that 267 is not divisible by 9.
Is 24207 divisible by 9?
Nope - in order for a number to be divisible by 9, the sum of its digits must also be divisible by 9. In this case, the digits 2+4+2+7=15.
Is 7 divisible by 9?
no 7 is divisible by 14. :)
What is the divisibility rule of 9?
If the sum of all the digits is divisible by 9, then the entire number is divisible by 9! For example: 9,728,127 is divisible by 9. 9+7+2+8+1+2+7=36, and I know 36 is divisible by 9. Therefore, the whole number is. 982 is not. 9+2+8=19. 19 is not divisible by 9.Works for really huge numbers too. 3,456,245,190,769,984,245,865,992,831 The sum of the digits is 144. Unsure if that works? Find the sum of THOSE digits (and keep doing that until you get something that you KNOW is divisible by 9). 1+4+4=9. That means the whole huge number is divisible by 9!
What is 17211 divisible by 2 3 4 5 6 9 10?
It is divisible only by 3; It is not divisible by 2, 4, 5, 6, 9, 10. 17211 is odd, so not divisible by 2, 4, 6 nor 10. 1 + 7 + 2 + 1 + 1 = 12 which is divisible by 3, so 17211 is divisible by 3, but 12 is not divisible by 9, so 17211 is not divisible by 9. 17211 does not end in 5 or 0 so not divisible by 5
Which one is NOT divisible by 9 234 345 or 567?
For each given number, add the digits. If the sum comes to nine, then it is divisible by '9'. 234 ; 2 + 3 + 4 = 9 So is dividble by '9' 345 ; 3 + 4 + 5 = 12 = 1 + 2 = 3 Not divisible by '9' 567 ; 5 + 6 + 7 = 18 = 1 + 8 = 9 so is divisible by '9'.
What are the prime numbers between 2 and 10?
3, 5, 7. 4, 6, and 8 are divisible by 2. 9 is divisible by 3.
What is divisible by 198 2 throw 10?
198 is divisible by 2, 3, 6 and 9, not by 4, 5, 7, 8 and 10.
What is the smallest number that is divisible by 2 3 4 5 6 7 8 9 and 10?
The smallest number that is divisible by 2 3 4 5 6 7 8 9 and 10 is 2,520.
Is 745 divisible by 2 3 5 9 or 10?
Out of that list, just 5. ------------------------------------------------ To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8} The last digit is 5 which is not even (it is odd), so 745 is not divisible by 2 To be divisible by 3 the sum of the digits must also be divisible by 3; if the summing is repeated until a single digit remains, then the original number is only divisible by 3 if this single digit is divisible by 3, ie it is one of {3, 6, 9} 745 → 7 + 4 + 5 = 16 16 + 1 + 6 = 7 7 is not divisible by 3 (it is not one of {3, 6, 9}), so 745 is not divisible by 3 To be divisible by 5, the last digit must be 0 or 5 The last digit of 745 is 5 which is one of {0, 5}, so 745 is divisible by 5 To be divisible by 9 the sum of the digits must also be divisible by 9; if the summing is repeated until a single digit remains, then the original number is only divisible by 9 if this single digit is 9 (otherwise this single digit gives the remainder when the original number is divided by 9) 745 + 7 + 4 + 5 = 16 16 → 1 + 6 = 7 7 is not 9, so 745 is not divisible by 9 (the remainder is 7) To be divisible by 10 the last digit must be 0 The last digit of 745 is 5 which is not 0, so 745 is not divisible by 10. 745 is not divisible by 2, 3, 9, 10 745 is divisible by 5.
Is 4828 divisible by 2 3 4 5 6 7 8 9 10 11?
4828 is divisible by 2 and 4 only.
