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The least number divisible by 1 2 3 4 and 6?
the least number divisible by 1, 2, 3, 4 & 6 is 12.
Is 1 2 0 3 8 divisible by 4 and 9?
1, 2, 0, 3 and 8 are not divisible by 4 and/or 9. Neither is 12038.
Is 143 divisible by 3?
1+4+3 = 8 which is not divisible by 3, so 143 is not divisible by 3. 8 ÷ 3 has remainder 2, so 143 ÷ 3 has remainder 2.
What are the divisibility rule for 6?
To be divisible by 6, the number must be divisible by both 2 and 3:To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8};To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3.As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3.If the number is not divisible by 2 or 3 (or both) then the number is not divisible by 6.examples:126Last digit is even so it is divisible by 2 1 + 2 + 6 = 9 which is divisible by 3, so it is divisible by 3→ 126 is divisible by both 2 and 3, so it is divisible by 6124Last digit is even so it is divisible by 2 1 + 2 + 4 = 7 which is not divisible by 3, so it is not divisible by 3→ 126 is divisible by 2 but not divisible by 3, so it is not divisible by 6123Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 3 = 6 which is divisible by 3, so it is divisible by 3→ 123 is divisible by 3 but not divisible by 2, so it is not divisible by 6121Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 1 = 4 which is not divisible by 3, so it is not divisible by 3→ 121 is not divisible by either 2 or 3, so it is not divisible by 6
If a number is divisible by 12 what other numbers is it divisible by?
1, 2, 3, 4, and 6
Is 1 2 0 3 6 divisible by 4 and 9?
not divisible by 9.but it is divisible by 4.
The least number divisible by 1 2 3 4 and 6?
the least number divisible by 1, 2, 3, 4 & 6 is 12.
Is it 1412 is divisible by 3?
no because: 1+4+1+2=8 and 8 is not divisible by 3.
Is 1 2 0 3 8 divisible by 4 and 9?
1, 2, 0, 3 and 8 are not divisible by 4 and/or 9. Neither is 12038.
Is 423 divisible by 6?
A number is divisible by 6 if it is divisible both by 2 and 3 1240 is even then is divisible by 2 1+2+4+0 = 7 which is not divisible by 3 then 1240 is not divisible by 3 Thus 1240 is not divisible by 6
What is 17211 divisible by 2 3 4 5 6 9 10?
It is divisible only by 3; It is not divisible by 2, 4, 5, 6, 9, 10. 17211 is odd, so not divisible by 2, 4, 6 nor 10. 1 + 7 + 2 + 1 + 1 = 12 which is divisible by 3, so 17211 is divisible by 3, but 12 is not divisible by 9, so 17211 is not divisible by 9. 17211 does not end in 5 or 0 so not divisible by 5
What is divisible by 352 1 2 3 4 5 6 8 9?
352 is divisible by 1, 2, 4 and 8; not by 3, 5, 6 and 9
What number is divisible by 3 1324 or 2463?
2463. The trick is that a number is divisible by 3 if and only if the sum of its digits is divisible by 3. 1+3+2+4 = 10 (not divisible by 3), while 2+4+6+3 = 15 (divisible by 3).
Is 113865 divisible by 3?
1+1+3+8+6+5 = 24 2+4=6 6 is divisible by 3 so 113865 is divisible by 3.
Is 143 divisible by 3?
1+4+3 = 8 which is not divisible by 3, so 143 is not divisible by 3. 8 ÷ 3 has remainder 2, so 143 ÷ 3 has remainder 2.
What is the divisibility of 4?
4 is divisible by 1, 2 and 4.
What are the divisibility rule for 6?
To be divisible by 6, the number must be divisible by both 2 and 3:To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8};To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3.As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3.If the number is not divisible by 2 or 3 (or both) then the number is not divisible by 6.examples:126Last digit is even so it is divisible by 2 1 + 2 + 6 = 9 which is divisible by 3, so it is divisible by 3→ 126 is divisible by both 2 and 3, so it is divisible by 6124Last digit is even so it is divisible by 2 1 + 2 + 4 = 7 which is not divisible by 3, so it is not divisible by 3→ 126 is divisible by 2 but not divisible by 3, so it is not divisible by 6123Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 3 = 6 which is divisible by 3, so it is divisible by 3→ 123 is divisible by 3 but not divisible by 2, so it is not divisible by 6121Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 1 = 4 which is not divisible by 3, so it is not divisible by 3→ 121 is not divisible by either 2 or 3, so it is not divisible by 6
