Yes. 312 / 3 = 104
Because, using your divisibility rules you know that the sum of the numbers (3+1+2) is 6 which is a multiple of 3. threfor you can say, that is does devide by three.
The numbers that are divisible by 312 are infinite. Four of them are: 312, 624, 936, 1248.
312 is divisible by 2 b/c the 2 at the end of 312 is an even number312 is divisible by 3 b/c 3 + 1 + 2 = 6 which is divisible by 3312 is divisible by 4 b/c 12 is divisible by 4312 is not divisible by 5 b/c the one's place isn't 0 or 5312 is divisible by 6 b/c 312 is divisible by 2 and 3312 is not divisible by 7 b/c 2*7=14, 31-14=17 which is not divisible by 7312 is divisible by 8 b/c 312/8=39 (Explanation: A way to find out how 8 is divisible its that its first three digits [the ones, tens, and hundreds place] have to be divisible by 8)312 is not divisible by 9 b/c 3 + 1 + 2 = 6 which is not divisible by 9312 is not divisible by 10 b/c the ones place is not 0
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 312 is a 2 which is NOT a 0, so 312 is NOT divisible by 10.
They are: 312 and its multiples
Because their quotient is a whole number.
624 is divisible by 312.
Yes.
The numbers that are divisible by 312 are infinite. Four of them are: 312, 624, 936, 1248.
312 is divisible by 2 b/c the 2 at the end of 312 is an even number312 is divisible by 3 b/c 3 + 1 + 2 = 6 which is divisible by 3312 is divisible by 4 b/c 12 is divisible by 4312 is not divisible by 5 b/c the one's place isn't 0 or 5312 is divisible by 6 b/c 312 is divisible by 2 and 3312 is not divisible by 7 b/c 2*7=14, 31-14=17 which is not divisible by 7312 is divisible by 8 b/c 312/8=39 (Explanation: A way to find out how 8 is divisible its that its first three digits [the ones, tens, and hundreds place] have to be divisible by 8)312 is not divisible by 9 b/c 3 + 1 + 2 = 6 which is not divisible by 9312 is not divisible by 10 b/c the ones place is not 0
Finding divisibility by 3 and 9 are very easy to do. Simply add up the digits in the number and see if they are divisible by the number you are looking for. 3+1+3=7 and 7 is not divisible by 3, is 313 is not either. ◄ 3+1+2=6 and 6 is divisible by 3, so 312 is also. 312/3=104
312 is divisible by 9 but the answer is not a whole number, it is... 34.666 recurring.
39, 78, 117, 195, 312 and 936 are divisible by three.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 312 is a 2 which is NOT a 0, so 312 is NOT divisible by 10.
Yes.
104 is divisible by 6?
They are: 312 and its multiples
Because their quotient is a whole number.