answersLogoWhite

0

325 is divisible by 5 leaving no remainder

User Avatar

Wiki User

9y ago

What else can I help you with?

Related Questions

Is 325 divisible by 5?

Yes - any number ending with a 0 or 5, including 325, is divisible by 5. In this instance, 325/5 = 65


Which of these numbers is divisible by 3 and 5 305 315 325 355?

Only 315. To be divisible by 3 numbers have to add to a number divisible by 3 (3+1+5 =9). To be disable by 5, number has to end in a 5 or 0


What is 650 divisible by?

650 is divisible by: 650 and 1 65 and 10 130 and 5 325 and 2


Is 230 divisible by 2 3 and 5?

yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!


What is 325 divisible by?

1, 5, 13, 25, 65, 325


Is 672 divisible by 5 10 2 3?

It is divisible by 2 and 3. It isn't divisible by 5 and 10.


Can 534 divisble by 2 3 5 9 10?

It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10


Is 432 divisible by 2 3 5 9 or 10?

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.


Is 5225 divisible by 3?

Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.


Is 535 divisible by 2 3 5 9 10?

535 is not divisible by 2, 3, 9, or 10. It is an odd number, so it cannot be divisible by 2. The sum of its digits (5 + 3 + 5 = 13) is not divisible by 3, and it does not end in 0 or 5, which means it is not divisible by 10. However, 535 is divisible by 5, as it ends with a 5.


Is 20 divisible by 2 3 5 9 or 10?

20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.


Is 1485 divisible by 2 3 5 6 9 and 10?

To determine if 1485 is divisible by 2, 3, 5, 6, 9, and 10, we can check each divisor. 1485 is odd, so it is not divisible by 2. It is divisible by 3 (since the sum of its digits, 1+4+8+5=18, is divisible by 3) and by 5 (it ends in 5). However, since it is not divisible by 2, it cannot be divisible by 6 or 10, and since it is not divisible by 9 (the sum of its digits is not divisible by 9), it is not divisible by that either. Thus, 1485 is only divisible by 3 and 5.