325 is divisible by 5 leaving no remainder
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Yes - any number ending with a 0 or 5, including 325, is divisible by 5. In this instance, 325/5 = 65
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
30 is divisible by, and is the least common multiple of, 2, 3, and 5.
One of the infinitely many integers divisible by 2, 3 and 5 is 3000.