Yes - any number ending with a 0 or 5, including 325, is divisible by 5. In this instance, 325/5 = 65
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
One of the infinitely many integers divisible by 2, 3 and 5 is 3000.
30 is divisible by, and is the least common multiple of, 2, 3, and 5.
Yes - any number ending with a 0 or 5, including 325, is divisible by 5. In this instance, 325/5 = 65
Only 315. To be divisible by 3 numbers have to add to a number divisible by 3 (3+1+5 =9). To be disable by 5, number has to end in a 5 or 0
650 is divisible by: 650 and 1 65 and 10 130 and 5 325 and 2
yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!
1, 5, 13, 25, 65, 325
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
The smallest number divisible by 2 3 5 is 30.
It is divisible by 2, 5 and 10, but not 3 and 9.