Q: Is 325 divisible by 4

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325 is divisible by 5 leaving no remainder

Yes - any number ending with a 0 or 5, including 325, is divisible by 5. In this instance, 325/5 = 65

All the multiples of 325 (which are infinite), starting with: 325, 650, 975, 1300, 1625, 1950, 2275 . . .

81.25

A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.

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325 is divisible by 5 leaving no remainder

Yes but they will all have remainders

Yes - any number ending with a 0 or 5, including 325, is divisible by 5. In this instance, 325/5 = 65

1, 5, 13, 25, 65, 325

108.33

108.3333

No. 10 does not evenly divide into 325, so it cannot be a factor of 325. Numbers that are divisible by 10 will end in a 0.

650 is divisible by: 650 and 1 65 and 10 130 and 5 325 and 2

All the multiples of 325 (which are infinite), starting with: 325, 650, 975, 1300, 1625, 1950, 2275 . . .

Yes, 975 / 3 = 325

2275 is the smallest number that is divisible by both 175 and 325. All multiples of 2275 are divisible by both these numbers. Ex: 2275 4550 6825 9100 and so on...

81.25