Yes because 36,297/9 = 4,033
No, both are divisible by 2.No, both are divisible by 2.No, both are divisible by 2.No, both are divisible by 2.
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.
416 is divisible by 2 but is not divisible by 3.
402 is divisible by 2.402 is divisible by 2.402 is divisible by 2.402 is divisible by 2.
3, 9, 37, 109, 111, 327, 333, 981, 4033, 12099.
Not evenly because it will have a remainder
Yes because 36,297/9 = 4,033
The factors of 36297 are 1, 3, 9, 37, 109, 111, 327, 333, 981, 4033, 12099, 36297. For them to be common, they need to be compared to another set of factors.
No, both are divisible by 2.No, both are divisible by 2.No, both are divisible by 2.No, both are divisible by 2.
351 is not divisible by 2. 2 is not divisible by 351.
2 is not divisible by 19008. 19008 is divisible by 2.
2 is not divisible by 972. 972 is divisible by 2.
2 is not divisible by 870. 870 is divisible by 2.
Of course not ! The answer is right within your question: 2 is divisible by 2 but 2 is not divisible by ... (can you dig it ?)
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.
123 is not divisible by 2 it is divisible by 3