Not evenly because it will have a remainder
3, 9, 37, 109, 111, 327, 333, 981, 4033, 12099.
Yes because 36,297/9 = 4,033
Any number is divisible by 2. I suspect you mean "without remainder", or "without having any fractional part left over". In this case No. And it is no for all odd numbers (those ending with 1,3,5,7 or 9) and yes for even numbers (those ending with 0,2,4,6 or 8).
The factors of 36297 are 1, 3, 9, 37, 109, 111, 327, 333, 981, 4033, 12099, 36297. For them to be common, they need to be compared to another set of factors.
If the last 3 digits are divisible by 8, the number is divisible by 8.
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.
Neither is divisible by 8.
152 is divisible by 8, and the answer is 19.
Not always for example, 36 is not divisible by 8 but it is divisible by 2 and 4.
4 is divisible by 1, 2 and 4. So is 8. If a number is divisible by 8, it will also be divisible by 4.
Yes. 8 / 4 = 2 8 is also divisible by 2 and 8.
Yes - 24 is divisible by both 6 and 8 - but is NOT divisible by 48