Yes - 3705/3 = 1235
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NO!!! To test divisibility by '9' add the digits. If the ddigits sum to '9' , then the number is divisible by '9' . Hence 3705 ; 3 + 7 + 0 + 5 = 15 = 1 + 5 = 6 So it does not add to '9' , so it is not divisible by '9'.
The multiples of 741 (which are infinite) are all divisible by 741, including these: 741, 1482, 2223, 2964, 3705, 4446, 5187, 5928, 6669 . . .
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
Not evenly. A number is divisible by 3 if the sum of its digits is divisible by 3.