No.
No it's not. To be divisible by five it has to end in either five or zero.
64.5
62 goes into 387 about 6 times.
387 divided by 6 is 64 with remainder 3.
387 is divisible by: 1 3 9 43 129 and 387.
No.
No it's not. To be divisible by five it has to end in either five or zero.
Yes. The sum of the digits is 18 which is divisible by 3.
64.5
64.5
62 of them.
1, 2, 3, 4, 6, 9, 12, 18, 36, 43, 86, 129, 172, 258, 387, 516, 774, 1548.
62 goes into 387 about 6 times.
6 is not divisible by 162. 162 is divisible by 6.
387 divided by 6 is 64 with remainder 3.
If it is divisible by 2 and 3, it is divisible by 6.