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d / t = s30 / 3 = 10 mphd = distancet = times = speed
sqrt (3)/(2) times A and -sqrt (3)/(2)
This is a simple question in algebra. Call the max speed of cheetah "x". Then the equation can be written: 3x -153 = 42 . That is, 3 times cheetah speed minus 153 = greyhound speed. So, adding 153 to both sides, 3x=42 + 153, or 3x=195. Dividing both sides by 3, we get x=65. THIS ANSWER IS WRONG!
It becomes a quarter as strong and a ninth as strong, respectively.
cheetah speed = x put it in an equation; 3x-153=42 so you do; 42+153=195 then; 195/3=64.3333333 cheetah speed= 64.333... rounded to 64mph.