You are missing either a + or a - in 32x 12y12
You must have meant either 32x+12y12 or 32x-12y12.
Also, if you probably meant to compare the two, they should have been equations to describe a line. Probably you meant 3x-8y12=0 and 32x+-12y12=0. Then you could have gotten the slope of the lines by rearranging the equations to the form y=mx+b. m is the slope of the line. If they have the same slope, they would be parallel. If they had opposite slope, they would be perpendicular. In this case, after rearranging the equations, you will find that they have neither the same slope nor opposite slopes; so they are neither parallel nor perpendicular.
If 32X + 53 = 501, then 32X = 448, and X = 448/32 = 14.
The answer is the expression 32x - 17.
32x + 8 – 34x
4x + 32x + 9 = 36x + 9
I read that as: (3) x (32x) x (3-2) - (32x) x (3) = 32x(3 x 3-2 - 3) = 32x (3-1 - 3) = 32x-1(1 - 32) = -8 x 32x-1 When multiplying the same base (number) to any power, keep the base and add the powers, eg: 32x x 3-1 = 32x + (-1) = 32x-1 3 x 3-2 = 31 x 3-2 = 31-2 = 3-1
32x-521 = -489
4y-32x = -28
Note that 16X is a factor of 32X [16X times 2 is 32X]. So now whether it's (32X)^4 or 32 times (X^4), that will still be the LCM, so the answer is 32X to the 4th power, just as it's stated in the question.
If 32X + 53 = 501, then 32X = 448, and X = 448/32 = 14.
48y - 32x
12x ^2 -32x-12
The answer is the expression 32x - 17.
32x + 8 – 34x
4x + 32x + 9 = 36x + 9
I read that as: (3) x (32x) x (3-2) - (32x) x (3) = 32x(3 x 3-2 - 3) = 32x (3-1 - 3) = 32x-1(1 - 32) = -8 x 32x-1 When multiplying the same base (number) to any power, keep the base and add the powers, eg: 32x x 3-1 = 32x + (-1) = 32x-1 3 x 3-2 = 31 x 3-2 = 31-2 = 3-1
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
Either: (7x + 4)(x + 4) = 7x2 + 32x + 16 or: (7x - 4)(x - 4) = 7x2 - 32x + 16