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Earn +20 ptsQ: Find the vertex and equation of the directri for y2 equals -32x?
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Find the equation of the axis symmetry and the coordinates of the vertex of the graph of each function for y equals 2x plus 4?
I'm assuming that you meant y = 2(x^2) +4. If it were only y = 2x +4, then this would be a linear equation and not a parabola. Anyways, use the equation x = -b/2a to find the x-value of your vertex AND your axis of symmetry. (Given the standard equation y = a(x^2) + bx + c) So, x = -0/2(2) - x = 0 (Axis of Symmetry) Now plug 0 back into your equation to find your y-value of your vertex. y = 2(0^2)+4 y=0 + 4 y = 4 Therefore Vertex = (0,4)
How would you use intercepts to find the vertex in a quadratic equation with two x intercepts?
The vertex must be half way between the two x intercepts
Find the value of x in the equation x-40 equals 60?
x=100
Where could i find a vertex?
You can find a vertex wherever two lines (or line segments) meet.
Find an equation of variation where y varies directly as x and y equals 500 when x equals 50?
y = 10x
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