if the number is a 2 or more diget number, you add up all of the numbers in the number and when you have the sum, if the sum is divisible by 3 , the whole number is divisible by three EX. 123=6, 6 is divisible by 3 so 123 is divisible by three 447=15 is divisible by 3 so 447 is divisible by 3 989=26 is *NOT* divisible by 3 so 989 is not divisible by three this truly does work for every single number
1, 3, 9, 27, 149, 447, 1341, 4023
1, 3, 5, 15, 149, 447, 745, 2235
1, 3, 5, 15, 149, 447, 745, 2235
447 is not a prime number. Other than 1 and itself, the positive integer factors of 447 are 3 and 149.
if the number is a 2 or more diget number, you add up all of the numbers in the number and when you have the sum, if the sum is divisible by 3 , the whole number is divisible by three EX. 123=6, 6 is divisible by 3 so 123 is divisible by three 447=15 is divisible by 3 so 447 is divisible by 3 989=26 is *NOT* divisible by 3 so 989 is not divisible by three this truly does work for every single number
1, 3, 9, 27, 149, 447, 1341, 4023
1, 3, 5, 15, 149, 447, 745, 2235
By these factors: 1, 2, 3, 6, 149, 298, 447, 894.
1, 3, 5, 15, 149, 447, 745, 2235
It is a composite Because 477 is divisible by 3 and because of that.... it makes it a composite because it is divisible by 1 and 3 PS I am just an ordinary 6th grade girl :)
1, 3, 149, 447
447 = 3 × 149
No, 447 is composite. Reason: 3 x 149 = 447.
3 x 149 = 447
447 is not a prime number. Other than 1 and itself, the positive integer factors of 447 are 3 and 149.
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.