No - 487/9 = 54.1 recurring (that is, 54.1111...)
No but it is divisible by: 1, 2, 487, 974, 10267, 20534, 5000029, and 10000058.
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
Not evenly. A number is divisible by 3 if the sum of its digits is divisible by 3.
6331 is divisible by 1, 13, 487, 6331
Only 487 and 1 because it is a prime number
No - 487/9 = 54.1 recurring (that is, 54.1111...)
Yes but it will have a remainder of one
No but it is divisible by: 1, 2, 487, 974, 10267, 20534, 5000029, and 10000058.
3214682/487 gives 6600 as quotient 482 remainder. Dividend-remainder=divisor*quotient 3214682-482 gives 3214200 which is divisible by 487. 482 can be subracted there are more possibility
Yes. 974/2 = 487. Any number that is an even number is divisible by 2.
The multiples of 6,331 (which are infinite) are all divisible by 6,331 including these: 6331, 12662, 18993, 25324 . . .
487 has three significant figures.
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.
It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.
A number is divisible by 3 if the sum of its digits is divisible by 3.