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∙ 15y ago3214682/487 gives 6600 as quotient 482 remainder. Dividend-remainder=divisor*quotient
3214682-482 gives 3214200 which is divisible by 487. 482 can be subracted there are more possibility
Karuna Saravana
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∙ 15y ago3214195
The multiple of 65 immediately less than 9400 is 9360. Therefore 40 has to be subtracted.
13801-55 = 13746 and 13746/87 = 158
what least number must be subtracted from 13081 to get a number exactly divisible by 87
It is: 16 because 18448-16 = 18432 and 18432/48 = 384
If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7.
Dividend-remainder= divisor*quotient 5694/43 give 132 quotient and 18 remainder.now 5694-18 =5676 is exactly divisible by 43. so 18 must be subracted.
The multiple of 65 immediately less than 9400 is 9360. Therefore 40 has to be subtracted.
13801-55 = 13746 and 13746/87 = 158
what least number must be subtracted from 13081 to get a number exactly divisible by 87
It is: 16 because 18448-16 = 18432 and 18432/48 = 384
If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7.
If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7.
The answer is 48illustration:833 is a multiple of 49 which is more than 832the multiple which is immediately less than 833 is 784so the difference that must be subtracted is 832- 784 = 48
If 'A' is 'divisible by 'B', it means that: -- If 'B' is repeatedly subtracted from 'A', then the last one fits exactly, without anything left over -- 'A' was made by piling up some whole number of 'B's, with no extras -- 'B' goes into 'A' evenly --'A'/'B'= some whole number
which least number should be subtracted from 1000 so that 30 divides the difference exactly
27836/56 gives 497 and 4 as quotient and remainder Dividend- remainder =27836-4 = 27832 which is divisible by 56. So the least no that to be subracted is 4
40 is nearest to 39 and is exactly by divisible 4