3214682/487 gives 6600 as quotient 482 remainder. Dividend-remainder=divisor*quotient
3214682-482 gives 3214200 which is divisible by 487. 482 can be subracted there are more possibility
The multiple of 65 immediately less than 9400 is 9360. Therefore 40 has to be subtracted.
13801-55 = 13746 and 13746/87 = 158
It is: 16 because 18448-16 = 18432 and 18432/48 = 384
If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7.
If 'A' is 'divisible by 'B', it means that: -- If 'B' is repeatedly subtracted from 'A', then the last one fits exactly, without anything left over -- 'A' was made by piling up some whole number of 'B's, with no extras -- 'B' goes into 'A' evenly --'A'/'B'= some whole number
18 must be subtracted from 5694 to get a number exactly divisible by 43
The multiple of 65 immediately less than 9400 is 9360. Therefore 40 has to be subtracted.
13801-55 = 13746 and 13746/87 = 158
To find the least number to be subtracted from 86295031 so that the remainder is divisible by 582, we first determine the remainder of 86295031 when divided by 582. Calculating (86295031 \mod 582) gives a remainder of 505. Therefore, to make the number exactly divisible by 582, we need to subtract this remainder, resulting in (505). Thus, the least number to subtract is 505.
To find the number that should be subtracted from 63700 to make it exactly divisible by 18, first, calculate the remainder when 63700 is divided by 18. Dividing 63700 by 18 gives a quotient of 3538 and a remainder of 16. Therefore, to make 63700 divisible by 18, you need to subtract this remainder (16) from 63700. Thus, subtracting 16 will yield 63684, which is divisible by 18.
It is: 16 because 18448-16 = 18432 and 18432/48 = 384
If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7.
If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7.
The answer is 48illustration:833 is a multiple of 49 which is more than 832the multiple which is immediately less than 833 is 784so the difference that must be subtracted is 832- 784 = 48
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
If 'A' is 'divisible by 'B', it means that: -- If 'B' is repeatedly subtracted from 'A', then the last one fits exactly, without anything left over -- 'A' was made by piling up some whole number of 'B's, with no extras -- 'B' goes into 'A' evenly --'A'/'B'= some whole number
which least number should be subtracted from 1000 so that 30 divides the difference exactly