Itself and 1 because 491 is a prime number
It is divisible by 10, but not by 235.
It is not divisible by 10. The remainder is 8.
460 is not divisible by 9, but it is divisible by 5 and 10.
If a number ends with 0, it is divisible by 10.If a number ends with 0, it is divisible by 10.If a number ends with 0, it is divisible by 10.If a number ends with 0, it is divisible by 10.
No
Itself and 1 because 491 is a prime number
491 is CDXCI. CD is 500 - 100. XC is 100 - 10. (I is 1.)
5's the obvious one, so we factor 5 out and get 1473. No more fives left, obviously, but 1473 follows the rule of factoring by 3 (1+4+7+3=15, which is divisible by three), so we factor 3 out and get 491. 491 isn't divisible by three 3, so we find the nearest square to 491, which is 484 (22*22). We test all the remaining prime numbers 22 or less: 7, 11, 13, 17, 19. None work, meaning 491 is prime. So the factors of 7365 are 3, 5, and 491.
80 is not divisible by 234569 but is divisible by 10.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
No, 204 is not divisible by 10. A number is only divisible by 10 if it ends in a 0.
No, 8648246286104 is not divisible by 10, but 8648246286104 is divisible by 2 and 8
No. 15, 25, 35, and 1675 are divisible by 5, but not by 10. However, every number divisible by 10 is also divisible by 5.
It is divisible by 10, but not by 235.
It is not divisible by 10. The remainder is 8.
460 is not divisible by 9, but it is divisible by 5 and 10.