No
No. In order for a number to be divisible by 10, the ones digit must be zero (0).
5's the obvious one, so we factor 5 out and get 1473. No more fives left, obviously, but 1473 follows the rule of factoring by 3 (1+4+7+3=15, which is divisible by three), so we factor 3 out and get 491. 491 isn't divisible by three 3, so we find the nearest square to 491, which is 484 (22*22). We test all the remaining prime numbers 22 or less: 7, 11, 13, 17, 19. None work, meaning 491 is prime. So the factors of 7365 are 3, 5, and 491.
491-216 = 275
1-492 = -491
Yes. 491 is prime.
There are 491 tenths in 491. This is because one whole number is equivalent to 10 tenths. Therefore, to find the number of tenths in 491, you simply multiply 491 by 10, giving you 4910 tenths.
491 multiplied by 3 is 1,473
491 + 284 = 775
0.0143
491 centimeters = 4.91 meters
491 metres = 1610.9 feet