cube root of 64 = 4 4 x 4 = 16, and 16 x 4 = 64 4 cube = 64
Suppose x3 = -64 then x3 + 64 = 0So (x + 4)*(x2 - 4x + 16) = 0So x = 4 or x = 2 +/- 2i*sqrt(3) where i is the imaginary square root of -1.-4 * -4 * -4 = -64So cube root of -64 = -4
The cube root of 64 is 4
This can be broken into cube root( 64 * 1000) = cube root(64) * cube root(1000) which is 4 * 10 = 40
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cube root of 64 = 4 4 x 4 = 16, and 16 x 4 = 64 4 cube = 64
the cube root of 64 =4
The cube root of 64 is 4. (4 x 4 x 4 = 64)
square root is 8 (8 x 8 = 64)cube root is 4 (4 x 4 x 4 = 64)
The cube root of 64 is 4.
Suppose x3 = -64 then x3 + 64 = 0So (x + 4)*(x2 - 4x + 16) = 0So x = 4 or x = 2 +/- 2i*sqrt(3) where i is the imaginary square root of -1.-4 * -4 * -4 = -64So cube root of -64 = -4
The cube root of 64 is 4
This can be broken into cube root( 64 * 1000) = cube root(64) * cube root(1000) which is 4 * 10 = 40
3√64 = 4
4
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