1, 2, 3, 6, 89, 178, 267, 534.
534 divided by 2 = 267
Yes, to check for divisibility by three, use the sum of digits method: 5 + 3 + 4 = 12. Twelve is divisible by 3, so 534 is also divisible by 3
It is evenly divisible by 2 and by 3.
Yes. 2670 / 5 = 534
1, 2, 3, 6, 89, 178, 267, 534.
1, 2, 3, 6, 89, 178, 267, 534.
No, but 534 is divisible by 2 and 3.
Out of that list, 534 is divisible by 2 and 3.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
534 divided by 2 = 267
Yes, to check for divisibility by three, use the sum of digits method: 5 + 3 + 4 = 12. Twelve is divisible by 3, so 534 is also divisible by 3
Oh, dude, let me break it down for you. So, to check if 2136 is divisible by 4, you just need to see if the last two digits of the number are divisible by 4. In this case, 36 is divisible by 4, so yeah, 2136 is divisible by 4. Easy peasy, right?
It is evenly divisible by 2 and by 3.
89
Yes. 2670 / 5 = 534
No. To test: add the digits together and if the sum is divisible by 9, so is the original number. The test can be repeated on the sum until a single digit remains. If this single digit is 9 then the [original] number is divisible by 9, otherwise it gives the remainder when the [original] number is divided by 9. 534 → 5 + 3 + 4 = 12 12 → 1 + 2 = 3 3 ≠ 0 so 12 is not divisible by 9 so 534 is not divisible by 9; the remainder when 534 is divided by 9 is 3.