No.
To test: add the digits together and if the sum is divisible by 9, so is the original number.
The test can be repeated on the sum until a single digit remains.
If this single digit is 9 then the [original] number is divisible by 9, otherwise it gives the remainder when the [original] number is divided by 9.
534 → 5 + 3 + 4 = 12
12 → 1 + 2 = 3
3 ≠ 0 so 12 is not divisible by 9 so 534 is not divisible by 9; the remainder when 534 is divided by 9 is 3.
It is evenly divisible by 2 and by 3.
534 divided by 2 = 267
Yes, because 534 divided by six is 89. 89 multiplied by six is 534.
1, 2, 3, 6, 89, 178, 267, 534.
Yes, to check for divisibility by three, use the sum of digits method: 5 + 3 + 4 = 12. Twelve is divisible by 3, so 534 is also divisible by 3
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
It is evenly divisible by 2 and by 3.
No, but 534 is divisible by 2 and 3.
Out of that list, 534 is divisible by 2 and 3.
2:yes 3:no ? 5:no 9:no ? 10:no
534 divided by 2 = 267
Yes, because 534 divided by six is 89. 89 multiplied by six is 534.
1, 2, 3, 6, 89, 178, 267, 534.
1, 2, 3, 6, 89, 178, 267, 534.
Yes, to check for divisibility by three, use the sum of digits method: 5 + 3 + 4 = 12. Twelve is divisible by 3, so 534 is also divisible by 3
Yes. 2670 / 5 = 534
to find out wheathr a certain number is divisible by 3 just add up the digits. for ex:- 534=5+3+4=12=1+2=3 since 3 is divisible by 3 therefore 534 is divisible by 3