Oh, dude, let me just crunch some numbers real quick for you. So, 567 divided by 4 equals 141.75. And since 141.75 isn't a whole number, you can't evenly divide 567 by 4. So, nope, 567 is not divisible by 4. Math can be a real party pooper sometimes, right?
Yes, 567 is divisible by 3. When you divide 567 by 3, you get an even quotient of 189.
composite number as it is divisible by 1, 3, 7, 9, etc
28/567 = 4/81
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
141.75
Yes, 567 is divisible by 3. When you divide 567 by 3, you get an even quotient of 189.
For each given number, add the digits. If the sum comes to nine, then it is divisible by '9'. 234 ; 2 + 3 + 4 = 9 So is dividble by '9' 345 ; 3 + 4 + 5 = 12 = 1 + 2 = 3 Not divisible by '9' 567 ; 5 + 6 + 7 = 18 = 1 + 8 = 9 so is divisible by '9'.
Yes because if you multiply 63 by 9 it will give you 567.
is 567 divisible by both 2 and 9
567 is divisible by 9. 32 and 133 are not.
9, 3, 63, 189
No, actually it isn't. 567 is divisible by 3.
1, 3, 9, 189, 567, 1701
567 x 4 = 2268
composite number as it is divisible by 1, 3, 7, 9, etc
28/567 = 4/81
-69