Yes because if you multiply 63 by 9 it will give you 567.
is 567 divisible by both 2 and 9
Only 234 is divisible by both 2 and 9.
443 + 567 = 1,010
1134 ÷ 2 = 567 Therefore, 567 + 567 = 1134.
Yes, 567 is divisible by 3. When you divide 567 by 3, you get an even quotient of 189.
Yes because if you multiply 63 by 9 it will give you 567.
is 567 divisible by both 2 and 9
567 is divisible by 9. 32 and 133 are not.
No, actually it isn't. 567 is divisible by 3.
1, 3, 9, 189, 567, 1701
567 ÷ 4 = 141.75 Therefore, if a decimal answer is acceptable, then yes. If an exact division without a remainder is wanted, then the answer must be, No.
For each given number, add the digits. If the sum comes to nine, then it is divisible by '9'. 234 ; 2 + 3 + 4 = 9 So is dividble by '9' 345 ; 3 + 4 + 5 = 12 = 1 + 2 = 3 Not divisible by '9' 567 ; 5 + 6 + 7 = 18 = 1 + 8 = 9 so is divisible by '9'.
composite number as it is divisible by 1, 3, 7, 9, etc
A prime number is a number with two and only two factors: 1 (also known as unity) and itself. A composite number is a number with more than two factors; in other words, it has at least one factor besides 1 and itself. 567 has factors other than 1 and itself, so it is not a prime number. For example, it is divisible by 3. (You can check this by adding the digits of the number: 5 + 6 + 7 = 18. If the sum of the digits is divisible by 3, the number is also divisible by 3.) Therefore, 567 is a composite number.
Only 234 is divisible by both 2 and 9.
1 and 567 are a factor pair of 567 since 1 x 567= 567 3 and 189 are a factor pair of 567 since 3 x 189= 567 7 and 81 are a factor pair of 567 since 7 x 81= 567 9 and 63 are a factor pair of 567 since 9 x 63= 567 21 and 27 are a factor pair of 567 since 21 x 27= 567