80 is divisible by 5 and 4 and is greater than 75
No, 80 is composite. it is divisible by 1, 2, 4, 5, 8, 10, 20, 40, and 80
90
1, 2, 4, 5, 8, 10, 16, 20, 40, 80
1, 2, 4, 5, 8, 10, 16, 20, 40, 80
80 is divisible by 5 and 4 and is greater than 75
No; it is divisible only by its factors (1, 2, 4, 5, 8, 10, 16, 20, 40, and 80).
To find a number between 80 and 100 that is divisible by both 5 and 6, we need to find the least common multiple (LCM) of 5 and 6, which is 30. We then look for a multiple of 30 between 80 and 100, which is 90. Therefore, the number 90 between 80 and 100 is divisible by both 5 and 6.
80 is not divisible by 234569 but is divisible by 10.
Factors of 80 = 1, 2, 4, 5, 8, 10, 16, 20, 40, 80.
No, 80 is composite. it is divisible by 1, 2, 4, 5, 8, 10, 20, 40, and 80
80
It is 90.
90
80%. Out of every ten numbers, one is divisible by 10, and that same one plus one moreare both divisible by 5. The remaining eight are divisible by neither 5 nor 10.
Yes, 5 is a factor of 80. It evenly divides into 80. Any integer ending in 0 or 5 is evenly divisible by 5, so all of those numbers have 5 as a factor. 5 x 16 = 80
Oh, dude, numbers that are divisible by both 4 and 5 are multiples of their least common multiple, which is 20. So, like, 20, 40, 60, and so on are all numbers that fit the bill. But hey, who's counting, right?